From: Thomas Gleixner <t...@linutronix.de> There is no generic way to test whether a kernel is running on a specific hypervisor. But that's required to prevent the upcoming user address space separation feature in certain guest modes.
Make the hypervisor type enum unconditionally available and provide a helper function which allows to test for a specific type. Signed-off-by: Thomas Gleixner <t...@linutronix.de> --- arch/x86/include/asm/hypervisor.h | 25 +++++++++++++++---------- 1 file changed, 15 insertions(+), 10 deletions(-) --- a/arch/x86/include/asm/hypervisor.h +++ b/arch/x86/include/asm/hypervisor.h @@ -20,16 +20,7 @@ #ifndef _ASM_X86_HYPERVISOR_H #define _ASM_X86_HYPERVISOR_H -#ifdef CONFIG_HYPERVISOR_GUEST - -#include <asm/kvm_para.h> -#include <asm/x86_init.h> -#include <asm/xen/hypervisor.h> - -/* - * x86 hypervisor information - */ - +/* x86 hypervisor types */ enum x86_hypervisor_type { X86_HYPER_NATIVE = 0, X86_HYPER_VMWARE, @@ -39,6 +30,12 @@ enum x86_hypervisor_type { X86_HYPER_KVM, }; +#ifdef CONFIG_HYPERVISOR_GUEST + +#include <asm/kvm_para.h> +#include <asm/x86_init.h> +#include <asm/xen/hypervisor.h> + struct hypervisor_x86 { /* Hypervisor name */ const char *name; @@ -58,7 +55,15 @@ struct hypervisor_x86 { extern enum x86_hypervisor_type x86_hyper_type; extern void init_hypervisor_platform(void); +static inline bool hypervisor_is_type(enum x86_hypervisor_type type) +{ + return x86_hyper_type == type; +} #else static inline void init_hypervisor_platform(void) { } +static inline bool hypervisor_is_type(enum x86_hypervisor_type type) +{ + return type == X86_HYPER_NATIVE; +} #endif /* CONFIG_HYPERVISOR_GUEST */ #endif /* _ASM_X86_HYPERVISOR_H */