On Tue, Dec 05, 2017 at 05:10:16PM +0000, Patrick Bellasi wrote:
> +static inline void util_est_dequeue(struct task_struct *p, int flags)
> +{
> +     struct cfs_rq *cfs_rq = &task_rq(p)->cfs;
> +     unsigned long util_last = task_util(p);
> +     bool sleep = flags & DEQUEUE_SLEEP;
> +     unsigned long ewma;
> +     long util_est;
> +
> +     if (!sched_feat(UTIL_EST))
> +             return;
> +
> +     /*
> +      * Update root cfs_rq's estimated utilization
> +      *
> +      * If *p is the last task then the root cfs_rq's estimated utilization
> +      * of a CPU is 0 by definition.
> +      *
> +      * Otherwise, in removing *p's util_est from its cfs_rq's
> +      * util_est_runnable we should account for cases where this last
> +      * activation of *p was longer then the previous ones.
> +      * Also in these cases we need to set 0 the estimated utilization for
> +      * the CPU.
> +      */
> +     if (cfs_rq->nr_running > 0) {
> +             util_est  = cfs_rq->util_est_runnable;
> +             util_est -= task_util_est(p);
> +             if (util_est < 0)
> +                     util_est = 0;
> +             cfs_rq->util_est_runnable = util_est;
> +     } else {
> +             cfs_rq->util_est_runnable = 0;
> +     }
> +
> +     /*
> +      * Skip update of task's estimated utilization when the task has not
> +      * yet completed an activation, e.g. being migrated.
> +      */
> +     if (!sleep)
> +             return;
> +
> +     /*
> +      * Skip update of task's estimated utilization when its EWMA is already
> +      * ~1% close to its last activation value.
> +      */
> +     util_est = p->util_est.ewma;
> +     if (abs(util_est - util_last) <= (SCHED_CAPACITY_SCALE / 100))
> +             return;

Isn't that computation almost as expensive as the stuff you're trying to
avoid?

> +     /*
> +      * Update Task's estimated utilization
> +      *
> +      * When *p completes an activation we can consolidate another sample
> +      * about the task size. This is done by storing the last PELT value
> +      * for this task and using this value to load another sample in the
> +      * exponential weighted moving average:
> +      *
> +      *      ewma(t) = w *  task_util(p) + (1 - w) ewma(t-1)
> +      *              = w *  task_util(p) + ewma(t-1) - w * ewma(t-1)
> +      *              = w * (task_util(p) + ewma(t-1) / w - ewma(t-1))
> +      *
> +      * Where 'w' is the weight of new samples, which is configured to be
> +      * 0.25, thus making w=1/4
> +      */
> +     p->util_est.last = util_last;
> +     ewma = p->util_est.ewma;
> +     if (likely(ewma != 0)) {

Why special case 0? Yes it helps with the initial ramp-on, but would not
an asymmetric IIR (with a consistent upward bias) be better?

> +             ewma   = util_last + (ewma << UTIL_EST_WEIGHT_SHIFT) - ewma;
> +             ewma >>= UTIL_EST_WEIGHT_SHIFT;
> +     } else {
> +             ewma = util_last;
> +     }
> +     p->util_est.ewma = ewma;
> +}

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