On Tue, 2017-12-12 at 11:01 -0800, Tejun Heo wrote:
> rules.  Unfortunatley, it contains quite a few holes.
          ^^^^^^^^^^^^^
          Unfortunately?

> While this change makes REQ_ATOM_COMPLETE synchornization unnecessary
                                            ^^^^^^^^^^^^^^^
                                            synchronization?

> --- a/block/blk-core.c
> +++ b/block/blk-core.c
> @@ -126,6 +126,8 @@ void blk_rq_init(struct request_queue *q, struct request 
> *rq)
>       rq->start_time = jiffies;
>       set_start_time_ns(rq);
>       rq->part = NULL;
> +     seqcount_init(&rq->gstate_seq);
> +     u64_stats_init(&rq->aborted_gstate_sync);
>  }
>  EXPORT_SYMBOL(blk_rq_init);

Sorry but the above change looks ugly to me. My understanding is that 
blk_rq_init() is only used inside the block layer to initialize legacy block
layer requests while gstate_seq and aborted_gstate_sync are only relevant
for blk-mq requests. Wouldn't it be better to avoid that blk_rq_init() is
called for blk-mq requests such that the above change can be left out? The
only callers outside the block layer core of blk_rq_init() I know of are
ide_prep_sense() and scsi_ioctl_reset(). I can help with converting the SCSI
code if you want.

> +     write_seqcount_begin(&rq->gstate_seq);
> +     blk_mq_rq_update_state(rq, MQ_RQ_IN_FLIGHT);
> +     blk_add_timer(rq);
> +     write_seqcount_end(&rq->gstate_seq);

My understanding is that both write_seqcount_begin() and write_seqcount_end()
trigger a write memory barrier. Is a seqcount really faster than a spinlock?

> 
> @@ -792,6 +811,14 @@ void blk_mq_rq_timed_out(struct request *req, bool 
> reserved)
>               __blk_mq_complete_request(req);
>               break;
>       case BLK_EH_RESET_TIMER:
> +             /*
> +              * As nothing prevents from completion happening while
> +              * ->aborted_gstate is set, this may lead to ignored
> +              * completions and further spurious timeouts.
> +              */
> +             u64_stats_update_begin(&req->aborted_gstate_sync);
> +             req->aborted_gstate = 0;
> +             u64_stats_update_end(&req->aborted_gstate_sync);

If a blk-mq request is resubmitted 2**62 times, can that result in the above
code setting aborted_gstate to the same value as gstate? Isn't that a bug?
If so, how about setting aborted_gstate in the above code to e.g. gstate ^ 
(2**63)?

> @@ -228,6 +230,27 @@ struct request {
>  
>       unsigned short write_hint;
>  
> +     /*
> +      * On blk-mq, the lower bits of ->gstate carry the MQ_RQ_* state
> +      * value and the upper bits the generation number which is
> +      * monotonically incremented and used to distinguish the reuse
> +      * instances.
> +      *
> +      * ->gstate_seq allows updates to ->gstate and other fields
> +      * (currently ->deadline) during request start to be read
> +      * atomically from the timeout path, so that it can operate on a
> +      * coherent set of information.
> +      */
> +     seqcount_t gstate_seq;
> +     u64 gstate;
> +
> +     /*
> +      * ->aborted_gstate is used by the timeout to claim a specific
> +      * recycle instance of this request.  See blk_mq_timeout_work().
> +      */
> +     struct u64_stats_sync aborted_gstate_sync;
> +     u64 aborted_gstate;
> +
>       unsigned long deadline;
>       struct list_head timeout_list;

Why are gstate and aborted_gstate 64-bit variables? What makes you think that
32 bits would not be enough?

Thanks,

Bart.

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