On May 30 2007 11:24, Nitin Gupta wrote: >> >> It is the bytestream (ip) that is reinterpreted as uint16_t. >> And I really doubt that the LZO author has a big-endian machine, >> given the days of ubiquitous x86. > >> le16_to_cpu it is. > > But then why you think it should be > le_16_cpu() -- how will this make any difference?
Like I said, we are reinterpreting the byte stream as a uint16_t (= reading from bytestream to CPU). While writing out an uint16_t as a bytestream is cpu_to_le16. > For your ref (from big_endian.h): > # define __cpu_to_le16(x) ((__force __le16)__swab16((x))) > # define __le16_to_cpu(x) __swab16((__force __u16)(__le16)(x)) Jan -- - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/