Justin Piszcz wrote:
I think that mem=8832M would work as well, to make the kernel use only
the memory that is marked cacheable. (It looks like this parameter
takes the highest memory address we want the kernel to use, not the
highest memory amount.)
--
Robert Hancock Saskatoon, SK, Canada
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Is 8832MB a typo? 8GB of memory is ~8192MB right? Did you mean 8132MB
or? Intel wants me to flash my bios and reset everything to the
defaults to see if it is still an issue, I'd prefer to try the mem=
option first.
I think 8832 should be right.. As far as I can tell, the number is the
highest memory address, not the amount of memory, and there are some
holes in the 3-4GB region.
--
Robert Hancock Saskatoon, SK, Canada
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Home Page: http://www.roberthancock.com/
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