From: "H. Peter Anvin" <h...@linux.intel.com>
There is no point in having two different sizes for the "default ldt";
a concept which is obsolete anyway. Since this is kernel-dependent
and not user-space dependent, a 32-bit app needs to be able to accept
the 64-bit value anyway, so use that value, which is the larger of the
two.
Signed-off-by: H. Peter Anvin (Intel) <h...@zytor.com>
Cc: Ingo Molnar <mi...@kernel.org>
Cc: Thomas Gleixner <t...@linutronix.de>
Cc: Andy Lutomirski <l...@kernel.org>
Cc: Chang S. Bae <chang.seok....@intel.com>
Cc: Markus T. Metzger <markus.t.metz...@intel.com>
---
arch/x86/kernel/ldt.c | 8 ++------
1 file changed, 2 insertions(+), 6 deletions(-)
diff --git a/arch/x86/kernel/ldt.c b/arch/x86/kernel/ldt.c
index 18e9f4c0633d..601d24268a99 100644
--- a/arch/x86/kernel/ldt.c
+++ b/arch/x86/kernel/ldt.c
@@ -383,12 +383,8 @@ static int read_ldt(void __user *ptr, unsigned long
bytecount)
static int read_default_ldt(void __user *ptr, unsigned long bytecount)
{
- /* CHECKME: Can we use _one_ random number ? */
-#ifdef CONFIG_X86_32
- unsigned long size = 5 * sizeof(struct desc_struct);
-#else
- unsigned long size = 128;
-#endif
+ const unsigned long size = 128;
+
if (bytecount > size)
bytecount = size;
if (clear_user(ptr, bytecount))
--
2.14.4
