SCHED_WARN_ON() is conditionally compiled depending on CONFIG_SCHED_DEBUG.
WARN_ON() and variants can be used in if() statements to take an action
in the unlikely case that the WARN_ON condition is true. This is supposed
to work independently of whether the warning is actually printed. However,
without CONFIG_SCHED_DEBUG, SCHED_WARN_ON() evaluates to false
unconditionally.

Change SCHED_WARN_ON() to not discard the WARN_ON condition, even without
CONFIG_SCHED_DEBUG, so that it can be used within if() statements as
expected.

Signed-off-by: Jan H. Schönherr <jscho...@amazon.de>
---
 kernel/sched/sched.h | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/kernel/sched/sched.h b/kernel/sched/sched.h
index 9ecbb57049a2..3e0ad36938fb 100644
--- a/kernel/sched/sched.h
+++ b/kernel/sched/sched.h
@@ -76,7 +76,7 @@
 #ifdef CONFIG_SCHED_DEBUG
 # define SCHED_WARN_ON(x)      WARN_ONCE(x, #x)
 #else
-# define SCHED_WARN_ON(x)      ({ (void)(x), 0; })
+# define SCHED_WARN_ON(x)      ({ unlikely(!!(x)); })
 #endif
 
 struct rq;
-- 
2.9.3.1.gcba166c.dirty

Reply via email to