When removing the explicit task_struct->pid usage I found that
proc_readfd_common() and proc_pident_readdir() get this field,
but do not use it at all. So this cleanup is a cheap help with
the task_struct->pid isolation.
Signed-off-by: Pavel Emelyanov <[EMAIL PROTECTED]>
---
fs/proc/base.c | 5 +----
1 files changed, 1 insertion(+), 4 deletions(-)
diff --git a/fs/proc/base.c b/fs/proc/base.c
index 2fb3dfc..79e1918 100644
--- a/fs/proc/base.c
+++ b/fs/proc/base.c
@@ -1434,7 +1434,7 @@ static int proc_readfd_common(struct fil
struct dentry *dentry = filp->f_path.dentry;
struct inode *inode = dentry->d_inode;
struct task_struct *p = get_proc_task(inode);
- unsigned int fd, tid, ino;
+ unsigned int fd, ino;
int retval;
struct files_struct * files;
struct fdtable *fdt;
@@ -1443,7 +1443,6 @@ static int proc_readfd_common(struct fil
if (!p)
goto out_no_task;
retval = 0;
- tid = p->pid;
fd = filp->f_pos;
switch (fd) {
@@ -1678,7 +1677,6 @@ static int proc_pident_readdir(struct fi
const struct pid_entry *ents, unsigned int nents)
{
int i;
- int pid;
struct dentry *dentry = filp->f_path.dentry;
struct inode *inode = dentry->d_inode;
struct task_struct *task = get_proc_task(inode);
@@ -1691,7 +1689,6 @@ static int proc_pident_readdir(struct fi
goto out_no_task;
ret = 0;
- pid = task->pid;
i = filp->f_pos;
switch (i) {
case 0:
-
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