One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example:
struct foo { int stuff; struct boo entry[]; }; instance = kzalloc(sizeof(struct foo) + count * sizeof(struct boo), GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com> --- fs/afs/security.c | 3 +-- 1 file changed, 1 insertion(+), 2 deletions(-) diff --git a/fs/afs/security.c b/fs/afs/security.c index 71e71c07568f..82753f3c097f 100644 --- a/fs/afs/security.c +++ b/fs/afs/security.c @@ -191,8 +191,7 @@ void afs_cache_permit(struct afs_vnode *vnode, struct key *key, * yet. */ size++; - new = kzalloc(sizeof(struct afs_permits) + - sizeof(struct afs_permit) * size, GFP_NOFS); + new = kzalloc(struct_size(new, permits, size), GFP_NOFS); if (!new) goto out_put; -- 2.21.0