Al Viro wrote:
> __func__ is C99, but it's not what __FUNCTION__ used to be - it's not a
> string literal. 6.4.2.2(1):
>
> The identifier __func__ shall be implicitly declared by the translator
> as if, immediately following the opening brace of each function definition,
> the declaration
> static const char __func__[] = "function-name";
> appeared, where function-name is the name of the lexically-enclosing function.
>
> IOW, it's a phase 7 (parsing and translation of translation units) and not
> phase 4 (preprocessor). Practical implications are:
> * _way_ fewer kludges
> * it happens after phase 6 (string literal concatenation)
> So __FUNCION__ " is called" within body of foo() would result in
> "foo is called" while __func__ "is called" is a syntax error.
>
> These days old gcc __FUNCTION__ is gone; it's a macro expanding to __func__,
> so behaviour does *not* match the original (see above).
so if I understand correctly, this requires a fix:
--
__FUNCTION__ is a macro expanding to __func__ and translated as if previously
in that function was declared:
static const char __func__[] = "function-name";
As is DEBUG() - when active - will produce a syntax error.
Signed-off-by: Roel Kluin <[EMAIL PROTECTED]>
---
diff --git a/drivers/pcmcia/au1000_xxs1500.c b/drivers/pcmcia/au1000_xxs1500.c
index ce9d5c4..855e1d6 100644
--- a/drivers/pcmcia/au1000_xxs1500.c
+++ b/drivers/pcmcia/au1000_xxs1500.c
@@ -56,7 +56,7 @@
#define PCMCIA_IRQ AU1000_GPIO_4
#if 0
-#define DEBUG(x,args...) printk(__FUNCTION__ ": " x,##args)
+#define DEBUG(x, args...) printk("%s: ", __func__, x, ##args)
#else
#define DEBUG(x,args...)
#endif
--
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