This is normally done by the generic entry code, but the
kernel_stack_overflow() flow bypasses it.
Reviewed-by: Alexander Potapenko <gli...@google.com>
Acked-by: Heiko Carstens <h...@linux.ibm.com>
Signed-off-by: Ilya Leoshkevich <i...@linux.ibm.com>
---
arch/s390/kernel/traps.c | 6 ++++++
1 file changed, 6 insertions(+)
diff --git a/arch/s390/kernel/traps.c b/arch/s390/kernel/traps.c
index 52578b5cecbd..dde69d2a64f0 100644
--- a/arch/s390/kernel/traps.c
+++ b/arch/s390/kernel/traps.c
@@ -27,6 +27,7 @@
#include <linux/uaccess.h>
#include <linux/cpu.h>
#include <linux/entry-common.h>
+#include <linux/kmsan.h>
#include <asm/asm-extable.h>
#include <asm/vtime.h>
#include <asm/fpu.h>
@@ -262,6 +263,11 @@ static void monitor_event_exception(struct pt_regs *regs)
void kernel_stack_overflow(struct pt_regs *regs)
{
+ /*
+ * Normally regs are unpoisoned by the generic entry code, but
+ * kernel_stack_overflow() is a rare case that is called bypassing it.
+ */
+ kmsan_unpoison_entry_regs(regs);
bust_spinlocks(1);
printk("Kernel stack overflow.\n");
show_regs(regs);
--
2.45.1
