On Fri, 2 Mar 2001, Richard B. Johnson wrote:
> Yes and no. It takes microseconds to call the kernel for anything (time
> getpid() ), so it seldom loops. All the kernel has to do is remember
Hi,
c0109286 system_call +<22/40> (0.21) pid(4265)
c011c7e7 sys_gettimeofday +<13/a8> (0.27) pid(4265)
c010e3b2 do_gettimeofday +<e/88> (0.48) pid(4265)
c01092aa ret_from_sys_call +<6/21> (0.76) pid(4265)
c0109286 system_call +<22/40> (0.19) pid(4265)
c0120b45 sys_getpid +<d/1c> (0.18) pid(4265)
c01092aa ret_from_sys_call +<6/21> (0.77) pid(4265)
^^^^ time in usecs
This is a 500Mhz PIII. It wouldn't take much more cpu/memory speed
to get under a usec. The overhead of calling the kernel on this box
is almost exactly 1 usec.
-Mike
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