On Wed, Dec 12, 2012 at 5:12 PM, Leon Romanovsky <l...@leon.nu> wrote:
> On Wed, Dec 12, 2012 at 7:05 AM, Fubo Chen <fubo.c...@gmail.com> wrote:
>>
>> On Wed, Dec 12, 2012 at 3:37 PM, Namjae Jeon <linkinj...@gmail.com> wrote:
>> > +       /* dot and dotdot dentries should have zero-value hash code */
>> > +       if (!memcmp(name, ".", 1) || !memcmp(name, "..", 2))
>> > +               return 0;
>>
>> That looks suspicious. If memcmp(name, "..", 2) == 0 then always
>> memcmp(name, ".", 1) == 0. Why two tests ?
>
> It is not the case vice versa, so you still need to do two checks.
> You need to distinguish dot(.), dotdot(..) and something with dot at
> the beginning (for example - .o)

Thanks for replying. I understand that the intention is what you
explained. But to me the code says something else: "if the first byte
of name is a dot, return 0". Did I see that correctly ?

Fubo.
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