On Mon, Jan 7, 2013 at 7:26 AM, Konrad Rzeszutek Wilk
<konrad.w...@oracle.com> wrote:
> On Fri, Jan 04, 2013 at 02:10:25PM -0800, Yinghai Lu wrote:
>> On Fri, Jan 4, 2013 at 1:02 PM, Shuah Khan <shuahk...@gmail.com> wrote:
>> > Pani'cing the system doesn't sound like a good option to me in this
>> > case. This change to disable swiotlb is made for kdump. However, with
>> > this change several system fail to boot, unless crashkernel_low=72M is
>> > specified.
>>
>> this patchset is new feature to put second kdump kernel above 4G.
>>
>> >
>> > I would the say the right approach to solve this would be to not
>> > change the current pci_swiotlb_detect_override() behavior and treat
>> > swiotlb =1 upon entry equivalent to swiotlb_force set.
>>
>> that will make intel system have to take crashkernel_low=72M too.
>> otherwise intel system will get panic during swiotlb allocation.
>
> Two things:
>
> 1). You need to wrap the 'is_enough_..' in CONFIG_KEXEC, which means
> that the function needs to go in a header file.
kdump is just one case, user still can boot the system with memmap=...
to hit the panic.
> 2). The check for 1MB is suspect. Why only 1MB? You mentioned it is
> b/c of crashkernel_low=72M (which I am not seeing in v3.8
> kernel-parameters.txt?
> Is that part of your mega-patchset?). Anyhow, there seems to be a
> disconnect -
> what if the user supplied crashkernel_low=27M? Perhaps the 'is_enough'
> should also parse the bootparams to double-check that there is enough
> low-mem space? But then if the kernel grows then 72M might not be enough
> -
> you might need 82M with 3.9.
again, could with memmap= include or exclude case, so parse boot command line
is not going to handle all the case.
>
> Perhaps a better way for this is to do:
> 1). Change 'is_enough' to check only for 4MB.
> 2). When booting as kexec, the SWIOTLB would only use 4MB instead of
> 64MB?
can not tell it is from kexec path. kexec just get boot loader type assigned.
>
> Or, we could also use the post-late SWIOTLB initialization similiary to
> how it was
> done on ia64. This would mean that the AMD VI code would just call the
> .. something like this - NOT tested or even compile tested:
>
> diff --git a/drivers/iommu/amd_iommu.c b/drivers/iommu/amd_iommu.c
> index c1c74e0..e7fa8f7 100644
> --- a/drivers/iommu/amd_iommu.c
> +++ b/drivers/iommu/amd_iommu.c
> @@ -3173,6 +3173,24 @@ int __init amd_iommu_init_dma_ops(void)
> if (unhandled && max_pfn > MAX_DMA32_PFN) {
> /* There are unhandled devices - initialize swiotlb for them
> */
> swiotlb = 1;
> + /* Late (so no bootmem allocator) usage and only if the early
> SWIOTLB
> + * hadn't been allocated (which can happen on kexec kernels
> booted
> + * above 4GB). */
> + if (!swiotlb_nr_tbl()) {
> + int retry = 3;
> + int mb_size = 64;
> + int rc = 0;
> +retry_me:
> + if (retry < 0)
> + panic("We tried setting %dMB for SWIOTLB but
> got -ENOMEM", mb_size << 1);
> + rc = swiotlb_late_init_with_default_size(mb_size *
> (1<<20));
> + if (rc) {
> + retry --;
> + mb_size >> 1;
> + goto retry_me;
> + }
> + dma_ops = &swiotlb_dma_ops;
> + }
> }
>
> amd_iommu_stats_init();
>
> And then the early SWIOTLB initialization for 64MB can fail and we are still
> OK.
no, that is overkill.
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