On 01/11/2013 01:17 AM, Morten Rasmussen wrote:
> On Sat, Jan 05, 2013 at 08:37:46AM +0000, Alex Shi wrote:
>> If the wake/exec task is small enough, utils < 12.5%, it will
>> has the chance to be packed into a cpu which is busy but still has space to
>> handle it.
>>
>> Signed-off-by: Alex Shi <alex....@intel.com>
>> ---
>> kernel/sched/fair.c | 51 +++++++++++++++++++++++++++++++++++++++++++++------
>> 1 file changed, 45 insertions(+), 6 deletions(-)
>>
>> diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
>> index 8d0d3af..0596e81 100644
>> --- a/kernel/sched/fair.c
>> +++ b/kernel/sched/fair.c
>> @@ -3471,19 +3471,57 @@ static inline int get_sd_sched_policy(struct
>> sched_domain *sd,
>> }
>>
>> /*
>> + * find_leader_cpu - find the busiest but still has enough leisure time cpu
>> + * among the cpus in group.
>> + */
>> +static int
>> +find_leader_cpu(struct sched_group *group, struct task_struct *p, int
>> this_cpu)
>> +{
>> + unsigned vacancy, min_vacancy = UINT_MAX;
>
> unsigned int?
yes
>
>> + int idlest = -1;
>> + int i;
>> + /* percentage the task's util */
>> + unsigned putil = p->se.avg.runnable_avg_sum * 100
>> + / (p->se.avg.runnable_avg_period + 1);
>
> Alternatively you could use se.avg.load_avg_contrib which is the same
> ratio scaled by the task priority (se->load.weight). In the above
> expression you don't take priority into account.
sure. but this seems more directly of meaningful.
>
>> +
>> + /* Traverse only the allowed CPUs */
>> + for_each_cpu_and(i, sched_group_cpus(group), tsk_cpus_allowed(p)) {
>> + struct rq *rq = cpu_rq(i);
>> + int nr_running = rq->nr_running > 0 ? rq->nr_running : 1;
>> +
>> + /* only pack task which putil < 12.5% */
>> + vacancy = FULL_UTIL - (rq->util * nr_running + putil * 8);
>
> I can't follow this expression.
>
> The variables can have the following values:
> FULL_UTIL = 99
> rq->util = [0..99]
> nr_running = [1..inf]
> putil = [0..99]
>
> Why multiply rq->util by nr_running?
>
> Let's take an example where rq->util = 50, nr_running = 2, and putil =
> 10. In this case the value of putil doesn't really matter as vacancy
> would be negative anyway since FULL_UTIL - rq->util * nr_running is -1.
> However, with rq->util = 50 there should be plenty of spare cpu time to
> take another task.
for this example, the util is not full maybe due to it was just wake up,
it still is possible like to run full time. So, I try to give it the
large guess load.
>
> Also, why multiply putil by 8? rq->util must be very close to 0 for
> vacancy to be positive if putil is close to 12 (12.5%).
just want to pack small util tasks, since packing is possible to hurt
performance.
>
> The vacancy variable is declared unsigned, so it will underflow instead
> of becoming negative. Is this intentional?
ops, my mistake.
>
> I may be missing something, but could the expression be something like
> the below instead?
>
> Create a putil < 12.5% check before the loop. There is no reason to
> recheck it every iteration. Then:
>
> vacancy = FULL_UTIL - (rq->util + putil)
>
> should be enough?
>
>> +
>> + /* bias toward local cpu */
>> + if (vacancy > 0 && (i == this_cpu))
>> + return i;
>> +
>> + if (vacancy > 0 && vacancy < min_vacancy) {
>> + min_vacancy = vacancy;
>> + idlest = i;
>
> "idlest" may be a bit misleading here as you actually select busiest cpu
> that have enough spare capacity to take the task.
Um, change to leader_cpu?
>
> Morten
>
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