>> + nr_running = rq->nr_running ? rq->nr_running : 1;
>
> This can be cleaned up with proper min/max().
yes, thanks
>
>> +
>> + return rt_util + cfs_util * nr_running;
>
> Should this nr_running consider tasks in cfs_rq only? Also it seems
> there's no upper bound so that it can possibly exceed FULL_UTIL.
Yes.
we need to consider task number:nr_running, otherwise cpu utilization
will never beyond FULL_UTIL, then we can not know if the cpu is overload.
So we need the possible maximum utilization bigger than FULL_UTIL.
>
--
Thanks
Alex
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