On Fri, Jun 14, 2013 at 12:33:27PM -0400, Steven Rostedt wrote:
> On Fri, 2013-06-14 at 09:21 -0700, Paul E. McKenney wrote:
>
> > > > > @@ -548,15 +556,35 @@ static void uprobe_trace_print(struct
> > > > > trace_uprobe *tu,
> > > > > /* uprobe handler */
> > > > > static int uprobe_trace_func(struct trace_uprobe *tu, struct pt_regs
> > > > > *regs)
> > > > > {
> > > > > - if (!is_ret_probe(tu))
> > > > > - uprobe_trace_print(tu, 0, regs);
> > > > > + struct ftrace_event_file **file;
> > > > > +
> > > > > + if (is_ret_probe(tu))
> > > > > + return 0;
> > > > > +
> > > > > + file = rcu_dereference_raw(tu->files);
> > >
> > > Why are you using rcu_dereference_raw() and not rcu_dereference(). The
> > > _raw() is a bit special, and unless you know what you are doing with RCU
> > > here, don't use it.
> > >
> > > As I see you using rcu_dereference_raw() all over this patch, along with
> > > mutexes, I believe that you are not using RCU correctly here.
> >
> > If irqs and preempt are disabled, I suggest using rcu_dereference_sched().
> > That is what it is there for. ;-)
>
> I believe this just copied what kprobes did, where irqs and preemption
> is disabled. I don't believe that these probes have that same luxury.
>
> But that begs the question. Should we convert the rcu_dereference_raw()
> in the kprobe code to rcu_dereference_sched()?
It makes a lot of sense to me, at least assuming no issues with the
interrupts being disabled, but the checks not spotting this. Here
is the check:
preempt_count() != 0 || irqs_disabled()
(With additional elaboration for if lockdep is enabled.)
Thanx, Paul
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