On 09/21/2013 02:34 PM, Oleg Nesterov wrote:
Peter, sorry for delay, I was sick.

On 09/17, Peter Hurley wrote:

On 09/15/2013 11:50 AM, Oleg Nesterov wrote:

Put the "!on_exit" check back to restore the old behaviour.

Cc: sta...@vger.kernel.org # v3.10+
Signed-off-by: Oleg Nesterov <o...@redhat.com>
Reported-by: Karel Srot <ks...@redhat.com>

Reviewed-by: Peter Hurley <pe...@hurleysoftware.com>

Thanks!

Can I ask the question? tty_signal_session_leader() is probably fine,
but it _looks_ buggy or at least confusing to me.

                do_each_pid_task(tty->session, PIDTYPE_SID, p) {
                        spin_lock_irq(&p->sighand->siglock);
                        if (p->signal->tty == tty) {
                                p->signal->tty = NULL;
                                /* We defer the dereferences outside fo
                                   the tasklist lock */
                                refs++;
                        }
                        if (!p->signal->leader) {
                                spin_unlock_irq(&p->sighand->siglock);
                                continue;
                        }
                        __group_send_sig_info(SIGHUP, SEND_SIG_PRIV, p);
                        __group_send_sig_info(SIGCONT, SEND_SIG_PRIV, p);
                        put_pid(p->signal->tty_old_pgrp);  /* A noop */
                        spin_lock(&tty->ctrl_lock);
                        tty_pgrp = get_pid(tty->pgrp);

I guess this can happen only once, so we could even add WARN_ON(tty_pgrp)
before get_pid(). But this look confusing, as if we can do get_pid()
multiple times and leak tty->pgrp.

                        if (tty->pgrp)
                                p->signal->tty_old_pgrp = get_pid(tty->pgrp);

else? We already did put_pid(tty_old_pgrp), we should clear it.

IOW, do you think the patch below makes sense or I missed something?
Just curious.

The code block you're referring to only executes once because there is
only one session leader.

Regards,
Peter Hurley

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