On Sat, Oct 12, 2013 at 05:58:50PM -0400, Santosh Shilimkar wrote: > From: Grygorii Strashko <grygorii.stras...@ti.com> > > When debugging is enabled (cmdline has "memblock=debug") the memblock > will display upper memory boundary per each allocated/freed memory range > wrongly. For example: > memblock_reserve: [0x0000009e7e8000-0x0000009e7ed000] > _memblock_early_alloc_try_nid_nopanic+0xfc/0x12c > > The 0x0000009e7ed000 is displayed instead of 0x0000009e7ecfff > > Hence, correct this by changing formula used to calculate upper memory > boundary to (u64)base + size - 1 instead of (u64)base + size everywhere > in the debug messages.
I kinda prefer base + size because it's easier to actually know the size but yeah, it should have been [base, base + size) and other places use base + size - 1 notation so it probably is better to stick to that. Maybe move this one to the beginning of the series? Acked-by: Tejun Heo <t...@kernel.org> Thanks. -- tejun -- To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to majord...@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
