All wake_futex() callers already verify that the we are not dealing with
a pi futex_q, so we can remove the redundant WARN() check, as this is never
triggered anyway.

Cc: Ingo Molnar <[email protected]>
Cc: Darren Hart <[email protected]>
Cc: Peter Zijlstra <[email protected]>
Cc: Thomas Gleixner <[email protected]>
Cc: Mike Galbraith <[email protected]>
Cc: Jeff Mahoney <[email protected]>
Cc: Linus Torvalds <[email protected]>
Cc: Scott Norton <[email protected]>
Cc: Tom Vaden <[email protected]>
Cc: Aswin Chandramouleeswaran <[email protected]>
Cc: Waiman Long <[email protected]>
Cc: Jason Low <[email protected]>
Signed-off-by: Davidlohr Bueso <[email protected]>
---
 kernel/futex.c | 3 ---
 1 file changed, 3 deletions(-)

diff --git a/kernel/futex.c b/kernel/futex.c
index e6ffe73..0768c68 100644
--- a/kernel/futex.c
+++ b/kernel/futex.c
@@ -844,9 +844,6 @@ static void wake_futex(struct futex_q *q)
 {
        struct task_struct *p = q->task;
 
-       if (WARN(q->pi_state || q->rt_waiter, "refusing to wake PI futex\n"))
-               return;
-
        /*
         * We set q->lock_ptr = NULL _before_ we wake up the task. If
         * a non-futex wake up happens on another CPU then the task
-- 
1.8.1.4

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