On Mon, 9 Dec 2013, H.J. Lu wrote:

> >> so that he could load his program compiled as PIE above 4GB.
> >> If kernel is changed not to honor it, his program won't work any more.
> >> In normal case, PIE has zero vaddr and this doesn't apply.
> >>
> >
> > That doesn't seem to be PIE at all, and if it is PIE, then it should be
> > relocatable (I agree btw with randomizing upward from the selected address.)
> 
> Kernel can consider PIE with non-zero vaddr isn't real PIE.

Why?

I still think PIE with non-zero vaddr should be randomized by putting 
random offset to the vaddr. Don't you think so? Why?

-- 
Jiri Kosina
SUSE Labs
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