On 02/20/2014 08:11 AM, Tejun Heo wrote:
> Hello, Lai.
> 
> On Wed, Feb 19, 2014 at 11:47:58AM +0800, Lai Jiangshan wrote:
>> If a worker is wokenup unexpectedly, it will start to work incorretly.
>> Although it hardly happen, we should catch it and wait for being started
>> if it does happen.
> 
> Can this actually happen?  If so, how?

I don't think it can happen.
It depends on the system outside of workqueue.

I'm afraid someone see the task and wake up it.
workqueue protect itself.

> 
>> Signed-off-by: Lai Jiangshan <[email protected]>
>> ---
>>  kernel/workqueue.c |    6 ++++++
>>  1 files changed, 6 insertions(+), 0 deletions(-)
>>
>> diff --git a/kernel/workqueue.c b/kernel/workqueue.c
>> index 82ef9f3..bee5fe1 100644
>> --- a/kernel/workqueue.c
>> +++ b/kernel/workqueue.c
>> @@ -2284,6 +2284,12 @@ static int worker_thread(void *__worker)
>>      struct worker *worker = __worker;
>>      struct worker_pool *pool = worker->pool;
>>  
>> +    if (WARN_ON_ONCE(!(worker->flags & WORKER_STARTED))) {
> 
> And if this is something which can legitimately happen, why are we
> triggering WARN on it?

If it happens, it means there is something wrong in the system.

> 
>> +            /* The worker is wokenup unexpectedly before started */
>> +            mutex_lock(&pool->manager_mutex);
>> +            mutex_unlock(&pool->manager_mutex);
> 
> And what does these mutex cycling achieve (they need comment)?

Synchronize the manager to finish.

> 
> Thanks.
> 

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