On Wed 07-05-14 12:15:29, Vladimir Davydov wrote:
> Instead of calling back to memcontrol.c from kmem_cache_create_memcg in
> order to just create the name of a per memcg cache, let's allocate it in
> place. We only need to pass the memcg name to kmem_cache_create_memcg
> for that - everything else can be done in slab_common.c.
> 
> Signed-off-by: Vladimir Davydov <[email protected]>

Seems good to me.
I would keep the comment about the static buffer as mentioned below.
Other than that
Acked-by: Michal Hocko <[email protected]>

[...]
> -char *memcg_create_cache_name(struct mem_cgroup *memcg,
> -                           struct kmem_cache *root_cache)
> -{
> -     static char *buf;
> -
> -     /*
> -      * We need a mutex here to protect the shared buffer. Since this is
> -      * expected to be called only on cache creation, we can employ the
> -      * slab_mutex for that purpose.
> -      */
> -     lockdep_assert_held(&slab_mutex);
> -
> -     if (!buf) {
> -             buf = kmalloc(NAME_MAX + 1, GFP_KERNEL);
> -             if (!buf)
> -                     return NULL;
> -     }
> -
> -     cgroup_name(memcg->css.cgroup, buf, NAME_MAX + 1);
> -     return kasprintf(GFP_KERNEL, "%s(%d:%s)", root_cache->name,
> -                      memcg_cache_id(memcg), buf);
> -}
> -
>  int memcg_alloc_cache_params(struct mem_cgroup *memcg, struct kmem_cache *s,
>                            struct kmem_cache *root_cache)
>  {
> @@ -3164,6 +3141,7 @@ void memcg_free_cache_params(struct kmem_cache *s)
>  static void memcg_kmem_create_cache(struct mem_cgroup *memcg,
>                                   struct kmem_cache *root_cache)
>  {
> +     static char *memcg_name_buf;
>       struct kmem_cache *cachep;
>       int id;

So we are relying on memcg_slab_mutex now, right? Worth a comment I
suppose.

-- 
Michal Hocko
SUSE Labs
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