yes, the callers guarantee that count > 0 here.

Regards, Ursula Braun

On Thu, 2014-05-22 at 12:14 +0200, Ursula Braun1 wrote:
> From:        Sebastian Ott <[email protected]> 
> To:        Joe Perches <[email protected]>, Ursula
> Braun1/Germany/IBM@IBMDE, 
> Cc:        Fabian Frederick <[email protected]>, linux-kernel
> <[email protected]>, akpm <[email protected]> 
> Date:        21/05/2014 14:32 
> Subject:        Re: [PATCH 1/1] drivers/s390/cio/qdio_main.c: replace
> shift loop by ilog2 
> 
> ______________________________________________________________________
> 
> 
> 
> On Tue, 20 May 2014, Joe Perches wrote:
> > On Tue, 2014-05-20 at 18:37 +0200, Fabian Frederick wrote:
> > > This is untested.
> > []
> > > diff --git a/drivers/s390/cio/qdio_main.c
> b/drivers/s390/cio/qdio_main.c
> > []
> > > @@ -411,15 +411,14 @@ static inline void qdio_stop_polling(struct
> qdio_q *q)
> > >  
> > >  static inline void account_sbals(struct qdio_q *q, int count)
> > >  {
> > > -                 int pos = 0;
> > > +                 int pos;
> > >  
> > >                   q->q_stats.nr_sbal_total += count;
> > >                   if (count == QDIO_MAX_BUFFERS_MASK) {
> > >                                    q->q_stats.nr_sbals[7]++;
> > >                                    return;
> > >                   }
> > > -                 while (count >>= 1)
> > > -                                  pos++;
> > > +                 pos = ilog2(count);
> > 
> > What guarantees count > 0 here?
> 
> We would already be screwed when called with count < 0. Ursula, do the
> callers assure that count is positive?
> 
> Regards,
> Sebastian
> > 
> > count may be better unsigned.
> > 
> > 


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