В Чт, 16/10/2014 в 09:59 +0200, Peter Zijlstra пишет:
> On Thu, Oct 16, 2014 at 01:46:07AM +0400, Kirill Tkhai wrote:
> > > --- x/kernel/sched/fair.c
> > > +++ x/kernel/sched/fair.c
> > > @@ -1165,7 +1165,7 @@ static void task_numa_compare(struct tas
> > >  
> > >   rcu_read_lock();
> > >   cur = ACCESS_ONCE(dst_rq->curr);
> > > - if (cur->pid == 0) /* idle */
> > > + if (is_idle_task(cur) || (curr->flags & PF_EXITING))
> > >           cur = NULL;
> > >  
> > >   /*
> > > 
> > 
> > Looks like, we have to use the same fix for task_numa_group().
> 
> Don't think so, task_numa_group() is only called from task_numa_fault()
> which is on 'current' and neither idle and PF_EXITING should be
> faulting.

Isn't task_numa_group() fully preemptible?

It seems cpu_rq(cpu)->curr is not always equal to p.

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