On Mon 27-07-15 10:58:50, Hidehiro Kawai wrote:
[...]
> @@ -1472,6 +1472,18 @@ void __weak crash_unmap_reserved_pages(void)
>  
>  void crash_kexec(struct pt_regs *regs)
>  {
> +     int old_cpu, this_cpu;
> +
> +     /*
> +      * `old_cpu == -1' means we are the first comer and crash_kexec()
> +      * was called without entering panic().
> +      * `old_cpu == this_cpu' means crash_kexec() was called from panic().
> +      */
> +     this_cpu = raw_smp_processor_id();
> +     old_cpu = atomic_cmpxchg(&panicking_cpu, -1, this_cpu);
> +     if (old_cpu != -1 && old_cpu != this_cpu)
> +             return;
> +
>       /* Take the kexec_mutex here to prevent sys_kexec_load
>        * running on one cpu from replacing the crash kernel
>        * we are using after a panic on a different cpu.
> @@ -1491,6 +1503,14 @@ void crash_kexec(struct pt_regs *regs)
>               }
>               mutex_unlock(&kexec_mutex);
>       }
> +
> +     /*
> +      * If we came here from panic(), we have to keep panicking_cpu
> +      * to prevent other cpus from entering panic().  Otherwise,
> +      * resetting it so that other cpus can enter panic()/crash_kexec().
> +      */
> +     if (old_cpu == this_cpu)
> +             atomic_set(&panicking_cpu, -1);

This do the opposite what the comment says, wouldn't it? You should
check old_cpu == -1. Also atomic_set doesn't imply memory barriers which
might be a problem.
-- 
Michal Hocko
SUSE Labs
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