On 26/08/2015:08:01:21 AM, Jeff Layton wrote:
> On Wed, 26 Aug 2015 17:22:25 +0530
> Pratyush Anand <pan...@redhat.com> wrote:
> 
> > Hi Jeff,
> > 
> > Thanks for your review comments.
> > 
> > On 26/08/2015:06:31:03 AM, Jeff Layton wrote:
> > > On Tue, 25 Aug 2015 11:34:19 +0530
> > > Pratyush Anand <pan...@redhat.com> wrote:
> > > >         TP_fast_assign(
> > > >                 __entry->xprt = xprt;
> > > > +               __entry->addr =
> > > > +                       xprt ? (struct sockaddr *)&xprt->xpt_remote : 
> > > > NULL;
> > > 
> > > I don't get it. It's not safe to save a pointer to xprt and dereference
> > > that in a tracepoint (and I understand why that is), but it is safe to
> > > save a pointer to a structure embedded inside of xprt? Shouldn't you be
> > > saving a copy of the entire sockaddr struct instead?
> > 
> > As far as "saving of a pointer to a structure embedded inside of xprt" is
> > concerned, I do not see any issue.
> > 
> > Its your take that what you want to print as your tracepoint print output. I
> > might be missing something..  However, I do not see any value addition in
> > printing address of a structure(located in ring buffer) where 
> > xprt->xpt_remote
> > has been copied.
> > 
> > > 
> > > Ahh, ok -- I think I see the confusion. %pIScp does not print the
> > > address of the sockaddr, but instead dereferences the pointer and
> > > prints it as a formatted address string. See pointer() in
> > > lib/vsprintf.c. You do want to save off a copy of the structure instead.
> > 
> > In my opinion, saving of structure would only be necessary if you want to 
> > access
> > element of the structure xprt->xpt_remote.
> > 
> > ~Pratyush
> 
> That's exactly what %pI does. Look at the pointer() function.

My bad..am a slow learner :(
Will send V2. Thanks for explaining.

~Pratyush
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