On 11/19, Paul E. McKenney wrote:
>
> On Mon, Nov 20, 2006 at 12:17:31AM +0300, Oleg Nesterov wrote:
> > 
> > It will wait for xxx_read_unlock() on reader's side. And for this reason
> > this idx in fact is not exactly wrong :)
> 
> I am not seeing this.
> 
> Let's assume sp->completed starts out zero.
> 
> o     CPU 0 starts executing xxx_read_lock(), but is interrupted
>       (or whatever) just before the atomic_inc().  Upon return,
>       it will increment sp->ctr[0].

Right.

> o     CPU 1 executes synchronize_xxx() to completion, which it
>       can because CPU 0 has not yet incremented the counter.
>       It waited on sp->ctr[0], and incremented sp->completed to 1.
> 
> o     CPU 0 returns from interrupt and completes xxx_read_lock(),
>       but has incremented sp->ctr[0].
> 
> o     CPU 0 continues into its critical section, picking up a
>       pointer to an xxx-protected data structure (or, in Jens's
>       case starting an xxx-protected I/O).
> 
> o     CPU 1 executes another synchronize_xxx().  This completes
>       immediately because it is waiting for sp->ctr[1] to go
>       to zero, but CPU 0 incremented sp->ctr[0].  (Right?)

Right!

> o     CPU 1 continues, either freeing a data structure while
>       CPU 0 is still referencing it, or, in Jens's case, completing
>       an I/O barrier while there is still outstanding I/O.
> 
> Or am I missing something?

No, it is me.

Alan, Paul, thanks a lot for your patience!

Oleg.

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