On Wed, 26 Jun 2002, Sridhar J (june end) wrote:

> Thanks to all of you who replied promptly to my question. I would like to
> clarify one thing. When I compiled the program using gcc, I tried typing
> a.out. When that didn't work, I did a ls -l which showed me a file called
> a.out*.
> 
> Doesn't it mean that a.out is in the current directory? So why I should go
> to a parent directory as in ./a.out to execute it?

yep (a.out is in the current directory).

You just stay in the directory where a.out is located. The first dot in
"./a.out" _means_ the current directory.

If you want to try it, try a "ls -l .", you should see the content of the
current directory (output should be the same as "ls -l").


HTH

--
Jos Lemmerling on Debian GNU/Linux                      jos(@)lemmerling(.net)




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