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zavandi wrote:
> I found some strange result. Here it is in its most simplified form I
> can think of.
>
> This command usually prints a few OKs, as expected:
>
> for ((i=0; i< 100000; i++)); do if [ $RANDOM -eq 0 ]; then echo OK; fi; done
>
> But this other command _never_ prints anything:
>
> for ((i=0; i< 100000; i++)); do if [ $RANDOM -eq 0 ]; then echo OK;
> fi; done | cat
>
> Why?
Interesting.... semi-educated wild guess: when you pipe two commands
together, the bash manpage says each command is executed as a seperate
process (i.e., in a subshell). It also says If RANDOM is unset, it
loses its special properties, even if it is subsequently reset. So, my
guess is the subshell your for loop runs in had its RANDOM unset (or
possibly was never set).
One thing that backs this up, is that enclosing the for loop in
parenthesis, which also makes it execute in a subshell, like so
(for ((i=0; i<100000; i++)); do
if [ $RANDOM -eq 0 ]; then
echo OK;
fi;
done)
Behaves the same way as piping it through cat.
for ((i=0; i<100000; i++)); do
if [ $RANDOM -eq 0 ]; then
echo OK;
fi;
done | cat
But, when I create a shell script file that only contains the for loop,
and execute it in a subshell (either by enclosing it it parenthesis or
piping it through cat), it works correctly:
~ $ cat random.sh
#!/bin/bash
for ((i=0; i<100000; i++)); do
if [ $RANDOM -eq 0 ]; then
echo OK;
fi;
done
~ $ (./random.sh)
OK
OK
OK
OK
~ $ ./random.sh | cat
OK
OK
OK
OK
So, that means either I'm wrong and it's not something to do with the
for loop being executed in a subshell, or else the bash script sets up
the subshell's environment so that RANDOM works correctly.
Anyway, good luck with whatever you're doing that needs this.
Conway S. Smith
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