Hello,
I am trying to write a script to organize/sort my music collection. All of
my music is arranged as Artist/Album folders with tracks within them, and
most of these names have spaces (if not other strange characters). The
script I am trying to get working needs to get all filenames in a
specified directory so that I can process each file at a time. I am trying
to do this as:
#!/bin/bash
# set_idv3_tags.sh
for directory in "$@"; do
if [[ -d "$directory" ]]; then
for f in `find $directory -iname '*mp3' `; do
echo "found mp3 file: $f"
done
fi
done
Obviously, $f is getting word-split at each space encountered in
$directory as well as in the filename. How can I set bash to give me an
array/variable that I loop over for each file found only, irrespective of
spaces without using sed to replace the spaces with _ etc.?
I did think of -print0, but could not get to loop over each file and I
prefer not to use ls. What are my options with bash, or is it just better
to get this written with Perl?
Thanks!
-K
--
The only way to keep your health is to eat what you don't want, drink
what you don't like, and do what you'd rather not. -- Mark Twain
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