What about just doing a
find . -printf "%T@ " -exec /bin/ls -ld {} \;|sort -rn|sed "s/[0-9]* //"
On Sat, 1 Jul 2000, Ray Olszewski wrote:
>> Date: Sat, 01 Jul 2000 08:34:43 -0700
>> From: Ray Olszewski <[EMAIL PROTECTED]>
>> To: Gerry Mullins <[EMAIL PROTECTED]>,
>> [EMAIL PROTECTED]
>> Subject: Re: Directory listing sorting (oops)
>>
>> At 07:58 PM 3/5/98 -0800, Gerry Mullins wrote:
>> >Try this: "ls -ltr" It will give you a long listing in reverse time
>> >order....the freshest files will be at the bottom of the listing.
>>
>> Thanks, Gerry, but I think you missed the important part of the original
>> question.
>>
>> What you suggest works fine for the files in one directory. But he wants to
>> get a listing that includes files in subdirectories (by including -R, the
>> recursion flag, in the ls options), and get a union list sorted by
>> timestamp. Procedures like the one you posted (one without the -r flag would
>> probably be better for his purposes) work fine for sorts that are directory
>> by directory, but they do not produce one unified list when used with the -R
>> flag.
>>
Dieter
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