On Thu, May 15, 2008 at 10:11:59AM +0200, andrzej zaborowski wrote:
> This doesn't change anything - since machine_is_... is not constant,
> the whole expression is not constant and is a syntax error.  The
> compiler needs to know at compile time whether to store a 0 or a 1 in
> the initialiser.

ugh, that's true :-p
forget about it.

-- 
Best Regards,

Felipe Balbi
[EMAIL PROTECTED]
http://blog.felipebalbi.com
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