Oleg Verych wrote:
> Your intro pseudo-code:
>
> | g() {
> | char c;
> | struct S s; /* packed or not */
> | (s.intfield)++;
> | f(&s);
> | }
>
> Due to `c', `s' gets to be unaligned, i.e. light turned before you've
> touched a switch: layout of `c' is independed, it's a byte, not followed
> by a byte, thus must be padded. No?.
No. If struct S is packed then its alignment is 1 and it will be
placed immediately after c.
This is not a bug, it is the intended consequence of declaring struct S
as packed. This is exactly why we must be careful about making such
declarations.
Phil.
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