Well, you said elegant: #!/bin/bash dir -1 filex* 2>&1 | grep "No such" if [ $? -eq 0 ] ; then echo Dont got one else echo Got one fi
There are two tricks in this simple script. $? returns the error code of the last command. That's grep, hopefully. Problem is, dir -1 doesn't send a message to stdout if no file is found, so you have to redirect stderr to stdout before piping it to grep. This next script takes advantage of the stdout stuff: #!/bin/bash a=`dir -1 filex*` if [ -z "$a" ] ; then echo Dont got one else echo Got one fi Note, I haven't tested these scripts very much. Joel On Sun, Jun 08, 2003 at 04:28:05PM -0500, Michael Hipp wrote: > Hello, first post (in a long time) ... > > I thought to do something like: > > if [ -f myfile* ]; then > # do something > fi > > That's to find if there are one or more like myfile001, myfile002, but > it reports an error "too many arguments" if there is more than one. Any > simple/elegant way to do this? > > Thanks, > Michael > > _______________________________________________ > Linux-users mailing list > [EMAIL PROTECTED] > Unsubscribe/Suspend/Etc -> http://www.linux-sxs.org/mailman/listinfo/linux-users _______________________________________________ Linux-users mailing list [EMAIL PROTECTED] Unsubscribe/Suspend/Etc -> http://www.linux-sxs.org/mailman/listinfo/linux-users
