On Fri, Jan 19, 2007 at 12:35:28PM +0200, Zsolt HAJDU wrote: > > > hogyan lehet megmondani egy processzrol, hogy mennyi > > swapet foglal? > > # top -p 7458 > PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND > 7458 root 16 0 8084 684 7168 S 0.0 0.3 0:00.08 smbd > --------------------------------------- > > SWAP = VIRT - RES = 8084 - 684 = 7400 [kbyte]
$ top -n 1 -b -p 22268 top - 12:27:30 up 28 days, 4:14, 11 users, load average: 0.02, 0.02, 0.00 Tasks: 1 total, 0 running, 1 sleeping, 0 stopped, 0 zombie Cpu(s): 6.1% us, 0.6% sy, 2.0% ni, 90.9% id, 0.4% wa, 0.0% hi, 0.0% si Mem: 1035780k total, 1019472k used, 16308k free, 286416k buffers Swap: 979956k total, 0k used, 979956k free, 334016k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME COMMAND 22268 atkosa 16 0 156m 71m 20m S 0.0 7.1 5:33 mozilla-bin Megis 0 a swap, tehat valahol ez is santit... -- Udvozlettel Zsiga _________________________________________________ linux lista - linux@mlf.linux.rulez.org http://mlf2.linux.rulez.org/mailman/listinfo/linux