On Fri, Jan 19, 2007 at 12:35:28PM +0200, Zsolt HAJDU wrote:
>
> > hogyan lehet megmondani egy processzrol, hogy mennyi
> > swapet foglal?
>
> # top -p 7458
> PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND
> 7458 root 16 0 8084 684 7168 S 0.0 0.3 0:00.08 smbd
> ---------------------------------------
>
> SWAP = VIRT - RES = 8084 - 684 = 7400 [kbyte]
$ top -n 1 -b -p 22268
top - 12:27:30 up 28 days, 4:14, 11 users, load average: 0.02, 0.02, 0.00
Tasks: 1 total, 0 running, 1 sleeping, 0 stopped, 0 zombie
Cpu(s): 6.1% us, 0.6% sy, 2.0% ni, 90.9% id, 0.4% wa, 0.0% hi, 0.0% si
Mem: 1035780k total, 1019472k used, 16308k free, 286416k buffers
Swap: 979956k total, 0k used, 979956k free, 334016k cached
PID USER PR NI VIRT RES SHR S %CPU %MEM TIME COMMAND
22268 atkosa 16 0 156m 71m 20m S 0.0 7.1 5:33 mozilla-bin
Megis 0 a swap, tehat valahol ez is santit...
--
Udvozlettel
Zsiga
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