Ed Swierk wrote:
> On 2/1/07, Carl-Daniel Hailfinger <[EMAIL PROTECTED]> wrote:
>> The code says something different.
>>
>> static void delayx(uint8_t value) {
>> int i;
>> for(i=0;i<0x8000;i++) {
>> outb(value, 0x80);
>> }
>> }
>>
>> The value is the POST code and has nothing to do with the delay.
>> So your patch changed the POST code from E8 (1000 mod 256) to 64 (100)
>> and called the delay function ten times.
>
> So delayx() actually sets the POST code by writing some value 32768
> times, has nothing to do with delay, and the comments about delay are
> completely irrelevant? My brain just exploded.
Prepare for more explosions. The POST code is written 32768 times and
a side effect of writing to an I/O port on x86 is that it takes ~3 usec
depending on whom you ask. Why writing the POST code, you ask? Simple.
Port 0x80 is probably the one I/O port with the least side effects.
Regards,
Carl-Daniel
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