On Wed, Feb 12, 2014 at 12:26:14PM +0100, Sebastian Hesselbarth wrote:
> You can cook it down to:
>
> m = matches;
> /* Check against matches without compatible string */
> while (m->name[0] || m->type[0] || m->compatible[0]) {
> if (!m->compatible[0] && of_match_type_or_name(node, m)
> return m;
> m++;
> }Will do. Thanks, Kevin
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