Thank you so much for your help, it seems so obvious to see it written
down!.
Could you help with one other thing? I'm trying to extract the directory
name to form a description for each path returned. This is what I have so
far:
for OUTPUT in $(find `pwd` -name google_transit.zip)
do
while IFS='/' read -ra $OUTPUT; do
echo " <bean
class=\"org.opentripplanner.graph_builder.model.GtfsBundle\">"
echo " <property name=\"path\" value=\""$OUTPUT"\"
/>"
echo " <property name=\"defaultAgencyId\"
value=\"""${OUTPUT[6]}""\" />"
echo " </bean>"
done
done
What am I doing wrong?
I was trying to follow this example:
http://stackoverflow.com/questions/918886/split-string-based-on-delimiter-in-bash
A line in OUTPUT could for example be the below. In this case I'd like to
extract "OId_LG"
"/home/andyt/projects/django-stringer/txc/OId_LG/GTFS/google_transit.zip"
Thanks!
On Thursday, 24 January 2013 13:24:45 UTC, Hermenegildo Konstantin wrote:
>
>
>
> Dana četvrtak, 24. siječnja 2013. 02:58:42 UTC+1, korisnik Andrew Taylor
> napisao je:
>>
>> Hi,
>>
>> I'm struggling to figure out if I can do this in bash - can anyone offer
>> me some advice? Within this folder:
>>
>> /projects/django-stringer/txc
>>
>> I have about 30 sub-folders. each one contains a folder within a folder
>> that contains a file called "google_transit.zip" I'd like to print out this
>> list of paths in full if I can. An example path would be:
>>
>> /home/andyt/projects/django-stringer/txc/OId_CW/GTFS/google_transit.zip
>>
>> Thanks!
>>
>> Andy
>>
>
> see here :
>
> http://stackoverflow.com/questions/246215/how-can-i-list-files-with-their-absolute-path-in-linux
>
> find `pwd` -name google_transit.zip
>
>
>
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