This is a bit of an abstract question by a person who is 1/3rd of the way through the 
McGraw text, but I just keep popping with questions.

What if I had the following:

>> f: func [ a /ref1 arg1 /ref2 arg2] [ either ref2 [ print "ref2" ] [ print "no ref2" 
>] ]
>> f/ref1 3 /ref2 4 1
no ref2
== 1
>>

how could I call the function "f" to make use of both refinements?



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