> ok. I think I get it now. Everything is basically done as a reference. Even setting words. This is much simpler than what I was thinking :-) Um... > a: 5 > b: a > > in this example, b is a reference to a (right?). Nope. b is set with the result of evaluating a. >> a: 5 == 5 >> b: a == 5 >> a: 3 == 3 >> a == 3 >> b == 5 > The thing that was confusing me was that the copy function doesn't always create a new copy. In deep series, it creates a reference to copied value....strange... > > By the way, is there any way to prove that b is a reference to a ( in the above example) ? I know you can do it if you set the value of as a series datatype (by using insert or other series function). But how do you prove that b references a for number datatypes? I showed above that b is not a reference to a. Here's another way to look at it. You could set the word "b" to have a value which is literally the word "a" - by doing this: >> b: 'a == a You could then see the value of the word "b" by >> get 'b == a or evaluting b >> b == a and combining >> get b == 3 Which evaluates b to a value, in this case a word, and then applies the get function to that value.
