Jim,
an easy way to have commands run synchronous would be to change
ScriptInterpreterPython::RunScriptBasedCommand() to run
"debugger.SetAsync(False)" before actually invoking the target function, and
"debugger.SetAsync(True)" immediately after.
Of course, one could add a --asynchronous flag to "command script add" and have
all commands added *without* this flag run synchronous through the above trick.
If you want, I can try to work on this in the coming days and let you have a
patch for this.
Otherwise, if the preferred idea is to leave it to the individual scripted
commands to pick their synchronicity, I guess it is safer to have the code in a
try-finally block, as in:
> def StepOver(debugger, args, result, dict):
> arg_split = args.split(" ")
> print type(arg_split)
> count = int(arg_split[0])
> try:
> debugger.SetAsync(False)
> for i in range(0,count):
> lldb.thread.StepOver(lldb.eOnlyThisThread)
> debugger.HandleCommand("fr var")
> print "step<%d>"%i
> finally:
> debugger.SetAsync (True)
Sincerely,
- Enrico Granata
On Nov 4, 2011, at 6:18 PM, Jim Ingham wrote:
> gdbrulez:lldb-clean/build/Debug > cat ~/Desktop/script.py
> #########################
> import lldb
> import sys
> import os
> import time
>
> def StepOver(debugger, args, result, dict):
> arg_split = args.split(" ")
> print type(arg_split)
> count = int(arg_split[0])
> debugger.SetAsync(False)
> for i in range(0,count):
> lldb.thread.StepOver(lldb.eOnlyThisThread)
> debugger.HandleCommand("fr var")
> print "step<%d>"%i
>
> debugger.SetAsync (True)
>
> def __lldb_init_module(debugger, session_dict):
> debugger.HandleCommand("command script add -f script.StepOver mysto")
> return None
>
> Be sure to set the debugger back to Async mode in the script when you're
> done. My guess is that the most useful way to run lldb "script" commands is
> to set them to synchronous mode by default. Or maybe this should be a flag
> on the "command script add"?
>
> Hope this helps,
>
> Jim
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