The code below fails to match the string "a" to the regex "^a$" on MacOSX if
both "REG_EXTENDED | REG_ENHANCED" are specified, but it will pass if just
REG_ENHANCED is used.
Can someone run this on linux to see if the code below fails as well on linux?
I want to make sure it isn't just an old version of regex we have in our libc...
#include <stdio.h>
#include <stdint.h>
#include <regex.h>
#define DEFAULT_REG_FLAGS (REG_EXTENDED | REG_ENHANCED)
int main (int argc, char const *argv[], char const *envp[])
{
regex_t re;
const char *regex_input = "a";
int err = regcomp (&re, "^a$", DEFAULT_REG_FLAGS);
if (err == 0)
{
err = regexec (&re, regex_input, 0, NULL, DEFAULT_REG_FLAGS);
if (err == 0)
{
puts("matched");
}
else
{
char error_str[2048];
const size_t actual_error_str_size = regerror(err, &re, error_str,
sizeof(error_str));
puts(error_str);
}
}
return 0;
}
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