https://bugs.llvm.org/show_bug.cgi?id=46029
Bug ID: 46029
Summary: inconsistent behaviors at -O3 (-O0 is correct)
Product: lldb
Version: unspecified
Hardware: PC
OS: Linux
Status: NEW
Severity: enhancement
Priority: P
Component: All Bugs
Assignee: lldb-dev@lists.llvm.org
Reporter: yangyib...@hust.edu.cn
CC: jdevliegh...@apple.com, llvm-b...@lists.llvm.org
Created attachment 23515
--> https://bugs.llvm.org/attachment.cgi?id=23515&action=edit
the binary
$ clang --version
clang version 11.0.0 (/home/yibiao/.cache/yay/llvm-git/llvm-project
871beba234a83a2a02da9dedbd59b91a1bfbd7af)
Target: x86_64-pc-linux-gnu
Thread model: posix
InstalledDir: /usr/bin
$ lldb --version
lldb version 11.0.0
clang revision 871beba234a83a2a02da9dedbd59b91a1bfbd7af
llvm revision 871beba234a83a2a02da9dedbd59b91a1bfbd7af
$ clang -g -O3 small.c
$ lldb a.out
(lldb) target create "a.out"
Current executable set to '/home/yibiao/Debugger/a.out' (x86_64).
(lldb) b 11
Breakpoint 1: where = a.out`foo + 214 at small.c:11:7, address =
0x0000000000401206
(lldb) r
Process 295458 launched: '/home/yibiao/Debugger/a.out' (x86_64)
Process 295458 exited with status = 0 (0x00000000)
(lldb) q
/************************************
As showed, when setting breakpoint on Line 11, lldb exit directly.
However, when step-i, Line 11 is hit by lldb as follow:
************************************/
$ lldb a.out
(lldb) target create "a.out"
Current executable set to '/home/yibiao/Debugger/a.out' (x86_64).
(lldb) b main
Breakpoint 1: where = a.out`main + 1 at small.c:15:3, address =
0x00000000004013b1
(lldb) r
Process 295500 launched: '/home/yibiao/Debugger/a.out' (x86_64)
Process 295500 stopped
* thread #1, name = 'a.out', stop reason = breakpoint 1.1
frame #0: 0x00000000004013b1 a.out`main at small.c:15:3
12 }
13
14 int main() {
-> 15 foo(2, 0);
16 return 0;
17 }
18
(lldb) si -c 19
Process 295500 stopped
* thread #1, name = 'a.out', stop reason = instruction step into
frame #0: 0x000000000040135e a.out`foo(r=4210760, n=0) at small.c:11:14
8
9 while(i-->0)
10 if(n==0 || c[r+i]==0)
-> 11 g[r+i] = 0;
12 }
13
14 int main() {
(lldb)
$ cat small.c
int g[10], c[10];
__attribute__ ((noinline))
void foo(int r, int n) {
int i=0;
if(r>g[r])
i=r;
while(i-->0)
if(n==0 || c[r+i]==0)
g[r+i] = 0;
}
int main() {
foo(2, 0);
return 0;
}
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