Hi,

I keep getting the following error sometimes not always.
I am using a RollingFileAppender.

The  error usually occurs at the start of the application.
But inspite of the error the log file gets created.

log4j:ERROR Failed to flush writer,
java.io.InterruptedIOException
        at java.io.FileOutputStream.writeBytes(Native Method)
        at java.io.FileOutputStream.write(FileOutputStream.java:212)
        at
java.io.OutputStreamWriter.flushBuffer(OutputStreamWriter.java:230)
        at java.io.OutputStreamWriter.flush(OutputStreamWriter.java:244)
        at org.apache.log4j.helpers.QuietWriter.flush(QuietWriter.java:49)
        at
org.apache.log4j.WriterAppender.subAppend(WriterAppender.java:309)
        at
org.apache.log4j.RollingFileAppender.subAppend(RollingFileAppender.java:294)
        at org.apache.log4j.WriterAppender.append(WriterAppender.java:157)
        at
org.apache.log4j.AppenderSkeleton.doAppend(AppenderSkeleton.java:251)
        at
org.apache.log4j.helpers.AppenderAttachableImpl.appendLoopOnAppenders(Append
erAttachableImpl.java:57)
        at org.apache.log4j.Category.callAppenders(Category.java:255)
        at org.apache.log4j.Category.forcedLog(Category.java:445)
        at org.apache.log4j.Category.debug(Category.java:312)
        at 

heres the configuration file

# Set root category priority to DEBUG and its only appender to A1.
log4j.rootCategory=DEBUG, Default , Console

# Default is set to file appender
log4j.appender.Default=org.apache.log4j.RollingFileAppender
log4j.appender.Default.MaxFileSize=5000kB
log4j.appender.Default.MaxBackupIndex=0
log4j.appender.Default.File=pi.log
# Truncate if it aleady exists.
log4j.appender.Default.Append=false

log4j.appender.Default.layout=org.apache.log4j.PatternLayout
log4j.appender.Default.layout.ConversionPattern=%p [%c{1}] %m%n

### The console appender
log4j.appender.Console=org.apache.log4j.ConsoleAppender
log4j.appender.Console.Threshold=INFO
log4j.appender.Console.layout=org.apache.log4j.PatternLayout
log4j.appender.Console.layout.ConversionPattern=%p [%c{1}] %m%n

Any ideas why ?

thanks,
Swaminathan G.

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