Check the Tomcat docs but one way is to add it to the CATALINA_OPTS
environment variable.
On 3/14/06, red phoenix <[EMAIL PROTECTED]> wrote:
> How to "Added -Dlog4j.debug to the command line"? Would you give me an
> example?
>
> On 3/14/06, James Stauffer <[EMAIL PROTECTED]> wrote:
> >
> > Verify that it is configured before you attempt to use a Logger.
> > Added -Dlog4j.debug to the command line to give you more info.
> >
> > On 3/14/06, red phoenix <[EMAIL PROTECTED]> wrote:
> > > I have some file like follows:
> > > C:\tomcat5\webapps\ROOT\WEB-INF\web.xml
> > > C:\tomcat5\webapps\ROOT\WEB-INF\conf\log4j.properties
> > > C:\tomcat5\webapps\ROOT\WEB-INF\classes\test\LogServlet.class
> > > C:\tomcat5\webapps\ROOT\WEB-INF\classes\abc\test.class
> > >
> > > and I use servlet to initial log4j,like follows:
> > >
> > > /*LogServlet.java*/
> > > package test;
> > > import javax.servlet.*;
> > > import javax.servlet.http.*;
> > > import org.apache.log4j.PropertyConfigurator;
> > > public class LogServlet extends HttpServlet{
> > > public void init() throws ServletException {
> > > String prefix = getServletContext().getRealPath("/");
> > > String file =
> > > getServletConfig().getInitParameter("log4j-config-file");
> > > if(file != null)
> > > PropertyConfigurator.configure(prefix + file);
> > > }
> > > public void doPost(HttpServletRequest request, HttpServletResponse
> > > response) throws ServletException, IOException{}
> > > }
> > >
> > > /*web.xml*/
> > > .......
> > > <servlet>
> > > <display-name>LogServlet</display-name>
> > > <servlet-name>LogServlet</servlet-name>
> > > <servlet-class>
> > > test.LogServlet
> > > </servlet-class>
> > > <init-param>
> > > <param-name>log4j-config-file</param-name>
> > > <param-value>
> > > /WEB-INF/conf/log4j.properties
> > > </param-value>
> > > </init-param>
> > > <load-on-startup>1</load-on-startup>
> > > </servlet>
> > >
> > > /*log4j.properties*/
> > > log4j.logger.A1=INFO, A1
> > > log4j.appender.A1=org.apache.log4j.ConsoleAppender
> > > log4j.appender.A1.layout=org.apache.log4j.PatternLayout
> > > log4j.appender.A1.layout.ConversionPattern=%m%n
> > >
> > > I find LogServlet execute successful,and then I write a class to write
> > > log,like follows:
> > >
> > > package abc;
> > > import org.apache.log4j.Logger;
> > > public class test{
> > > private static Logger log;
> > > public static void main(String args[]){
> > > Logger log=Logger.getLogger("A1");
> > > log.error("test");
> > > }
> > >
> > > When I run test.class,I got error:
> > >
> > > log4j:WARN No appenders could be found for logger (A1).
> > > log4j:WARN Please initialize the log4j system properly.
> > >
> > > Why raise above error? I am puzzled with it.
> > > Thanks in advance.
> > >
> > >
> >
> >
> > --
> > James Stauffer
> > Are you good? Take the test at http://www.livingwaters.com/good/
> >
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> > For additional commands, e-mail: [EMAIL PROTECTED]
> >
> >
>
>
--
James Stauffer
Are you good? Take the test at http://www.livingwaters.com/good/
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