On Tue, Feb 27, 2001 at 01:46:49PM +0000, Piers Cawley wrote:
> That's almost as good as (¬)^0.5.
I was thinking about that on the way to work.
AIUI, square roots apply to numbers, so how can you have a square root of
something that isn't a number, like an operator? You may as well say that
you can take the square root of anything - like the square root of equals,
or the square root of a pony.
Calling that thing the square root of an operator is a bit misleading to
say the least. OK, it may appear to have some properties of a square root
operation, but a square root it ain't.
YMMV, cos IANAQM (but it would be helpful in debugging landrovers)
--
David Cantrell | [EMAIL PROTECTED] | http://www.cantrell.org.uk/david/
Any technology distinguishable from magic is insufficiently advanced
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