On Mon, Sep 24, 2001 at 12:09:19PM -0400, David H. Adler wrote:
> On Mon, Sep 24, 2001 at 11:35:19AM +0200, Paul Johnson wrote:
> > On Mon, Sep 24, 2001 at 01:15:06AM -0400, David H. Adler wrote:
> >
> > > On the other hand, given the wording of this, I find this slightly
> > > odd:
> > >
> > > bash-2.05$ perl -e ' $i = (-3..0);print "*$i*\n"'
> > > **
> > >
> > > ...as the right operand is false.
> > >
> > > Or am I misreading this?
> >
> > I think that what you are missing is that .. compares its constant
> > operands to $. Thus it is only really useful within an input loop and
> > with numbers which can match $.
> >
> > In this case $. != -3 so $i is false.
>
> In that case, why does (0..4) return a false value? The comparison of 0
> to $. is true,
$. isn't unundefed until it's read from:
$ perl -lwe 'print $.; <>; print $.'
Use of uninitialized value in print at -e line 1.
some stdin
1
$
Paul
