Hello,
Following are the steps I did:
usttrace -o /home/root ./Hello.out &
In /home/root, 2 folders were created:
656_-518...
This directory contains 1 file: metadata_0
656_-523...
This directory contains 1 file: ust_0
My code is:
#include <ust/marker.h>
int main (void)
{
int v=1;
char *st="trace";
while (1)
{
ust_marker (myevent,"firstarg %d secondarg %s",v,st);
sleep (1);
}
}
When I ran:
ustctl list-markers 656
I got the following:
....
{PID 656, channel/marker: ust/myevent, state: 1, fmt: "firstarg %d secondarg %s (nil)}
{PID 656, channel/marker: ust/myevent, state: 1, fmt: "firstarg %d secondarg %s (nil)}
So I think "myevent" is enabled.
But where the markers are logged ?
Where is the input file to lttv-gui ?
I'm running under busybox. Is it a problem ?
Thanks,
Zvika
נושא: RE: [ltt-dev] usttrace: directory of output trace
|
And it's not there under some hidden directory, i.e /home/root/.usttrace?
Can you run the examples under tests? (there are hello, hello2, basic, fork examples there)
Another option is to run it manually, try with a verbose option.
Start the daemon
ust-consumerd -d
then start your process, then see the markers with ustctl, enable them with ustctl, start tracing though ustctl command
From: צהלול לא קיים [mailto:[email protected]] Sent: August-23-11 6:50 AM To: [email protected] Subject: [ltt-dev] usttrace: directory of output trace Hello,
I have a simple program that creates 2 threads.
Each thread calls to: ust_marker (myotherevent,MARK_NOARGS) every 1 second.
The thread also prints a message (using printf) every 1 second.
The main thread loops forever doing only "sleep (1)".
I ran the program using: usttrace MyProg.out -o /home/root &
After a few seconds I checked the folder /home/root. It does not contain a trace file.
Can you help ?
Thanks, Zvika.
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