Le 02/04/2024 à 14:12, Kornel Benko a écrit :
The first one looks like a matter of old gcc that does not like the {}
constructor (don't remember the name).
JMarc
If so, can something be done here?
This compiles fine here, can you check that it does for you too?
Also, I do not know how to test this code. Riki can you confirm that it
makes sense?
JMarc
From 62d212a2f0c7ff851f03aa4c4fd5c9d138f9b4a1 Mon Sep 17 00:00:00 2001
From: Jean-Marc Lasgouttes <lasgout...@lyx.org>
Date: Wed, 3 Apr 2024 14:49:13 +0200
Subject: [PATCH] Construct tuple explicitly for older compilers
gcc < 6 refuses to use {foo, bar, baz} to construct a tuple in this context.
---
src/frontends/qt/GuiRef.cpp | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/src/frontends/qt/GuiRef.cpp b/src/frontends/qt/GuiRef.cpp
index 6a2446a5a6..f400aae8eb 100644
--- a/src/frontends/qt/GuiRef.cpp
+++ b/src/frontends/qt/GuiRef.cpp
@@ -455,7 +455,8 @@ void GuiRef::redoRefs()
for (auto const & theref : refs_) {
// first: plain label name, second: gui name, third: pretty name
QString const lab = toqstr(get<0>(theref));
- refsNames.append({lab, toqstr(get<1>(theref)), toqstr(get<2>(theref))});
+ // {a, b, c} is nicer, but gcc < 6 barks on it
+ refsNames.append(make_tuple(lab, toqstr(get<1>(theref)), toqstr(get<2>(theref))));
if (groupCB->isChecked()) {
if (lab.contains(":")) {
QString const pref = lab.split(':')[0];
--
2.25.1
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